3.702 \(\int \frac{x^4 (a+b x^3)^{4/3}}{c+d x^3} \, dx\)

Optimal. Leaf size=334 \[ -\frac{\left (2 a^2 d^2-12 a b c d+9 b^2 c^2\right ) \log \left (\sqrt [3]{b} x-\sqrt [3]{a+b x^3}\right )}{18 b^{2/3} d^3}-\frac{\left (2 a^2 d^2-12 a b c d+9 b^2 c^2\right ) \tan ^{-1}\left (\frac{\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1}{\sqrt{3}}\right )}{9 \sqrt{3} b^{2/3} d^3}-\frac{c^{2/3} (b c-a d)^{4/3} \log \left (c+d x^3\right )}{6 d^3}+\frac{c^{2/3} (b c-a d)^{4/3} \log \left (\frac{x \sqrt [3]{b c-a d}}{\sqrt [3]{c}}-\sqrt [3]{a+b x^3}\right )}{2 d^3}+\frac{c^{2/3} (b c-a d)^{4/3} \tan ^{-1}\left (\frac{\frac{2 x \sqrt [3]{b c-a d}}{\sqrt [3]{c} \sqrt [3]{a+b x^3}}+1}{\sqrt{3}}\right )}{\sqrt{3} d^3}-\frac{x^2 \sqrt [3]{a+b x^3} (6 b c-7 a d)}{18 d^2}+\frac{b x^5 \sqrt [3]{a+b x^3}}{6 d} \]

[Out]

-((6*b*c - 7*a*d)*x^2*(a + b*x^3)^(1/3))/(18*d^2) + (b*x^5*(a + b*x^3)^(1/3))/(6*d) - ((9*b^2*c^2 - 12*a*b*c*d
+ 2*a^2*d^2)*ArcTan[(1 + (2*b^(1/3)*x)/(a + b*x^3)^(1/3))/Sqrt[3]])/(9*Sqrt[3]*b^(2/3)*d^3) + (c^(2/3)*(b*c -
a*d)^(4/3)*ArcTan[(1 + (2*(b*c - a*d)^(1/3)*x)/(c^(1/3)*(a + b*x^3)^(1/3)))/Sqrt[3]])/(Sqrt[3]*d^3) - (c^(2/3
)*(b*c - a*d)^(4/3)*Log[c + d*x^3])/(6*d^3) - ((9*b^2*c^2 - 12*a*b*c*d + 2*a^2*d^2)*Log[b^(1/3)*x - (a + b*x^3
)^(1/3)])/(18*b^(2/3)*d^3) + (c^(2/3)*(b*c - a*d)^(4/3)*Log[((b*c - a*d)^(1/3)*x)/c^(1/3) - (a + b*x^3)^(1/3)]
)/(2*d^3)

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Rubi [C]  time = 0.0590289, antiderivative size = 65, normalized size of antiderivative = 0.19, number of steps used = 2, number of rules used = 2, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.083, Rules used = {511, 510} \[ \frac{a x^5 \sqrt [3]{a+b x^3} F_1\left (\frac{5}{3};-\frac{4}{3},1;\frac{8}{3};-\frac{b x^3}{a},-\frac{d x^3}{c}\right )}{5 c \sqrt [3]{\frac{b x^3}{a}+1}} \]

Warning: Unable to verify antiderivative.

[In]

Int[(x^4*(a + b*x^3)^(4/3))/(c + d*x^3),x]

[Out]

(a*x^5*(a + b*x^3)^(1/3)*AppellF1[5/3, -4/3, 1, 8/3, -((b*x^3)/a), -((d*x^3)/c)])/(5*c*(1 + (b*x^3)/a)^(1/3))

Rule 511

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Dist[(a^IntPa
rt[p]*(a + b*x^n)^FracPart[p])/(1 + (b*x^n)/a)^FracPart[p], Int[(e*x)^m*(1 + (b*x^n)/a)^p*(c + d*x^n)^q, x], x
] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] &&  !(IntegerQ[
p] || GtQ[a, 0])

Rule 510

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(a^p*c^q
*(e*x)^(m + 1)*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, -((b*x^n)/a), -((d*x^n)/c)])/(e*(m + 1)), x] /; Free
Q[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a
, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rubi steps

\begin{align*} \int \frac{x^4 \left (a+b x^3\right )^{4/3}}{c+d x^3} \, dx &=\frac{\left (a \sqrt [3]{a+b x^3}\right ) \int \frac{x^4 \left (1+\frac{b x^3}{a}\right )^{4/3}}{c+d x^3} \, dx}{\sqrt [3]{1+\frac{b x^3}{a}}}\\ &=\frac{a x^5 \sqrt [3]{a+b x^3} F_1\left (\frac{5}{3};-\frac{4}{3},1;\frac{8}{3};-\frac{b x^3}{a},-\frac{d x^3}{c}\right )}{5 c \sqrt [3]{1+\frac{b x^3}{a}}}\\ \end{align*}

Mathematica [C]  time = 0.267245, size = 225, normalized size = 0.67 \[ \frac{2 x^5 \left (\frac{b x^3}{a}+1\right )^{2/3} \left (\frac{d x^3}{c}+1\right )^{2/3} \left (2 a^2 d^2-12 a b c d+9 b^2 c^2\right ) F_1\left (\frac{5}{3};\frac{2}{3},1;\frac{8}{3};-\frac{b x^3}{a},-\frac{d x^3}{c}\right )+5 c x^2 \left (a \left (\frac{b x^3}{a}+1\right )^{2/3} (6 b c-7 a d) \, _2F_1\left (\frac{2}{3},\frac{2}{3};\frac{5}{3};\frac{(a d-b c) x^3}{a \left (d x^3+c\right )}\right )+\left (a+b x^3\right ) \left (\frac{d x^3}{c}+1\right )^{2/3} \left (7 a d-6 b c+3 b d x^3\right )\right )}{90 c d^2 \left (a+b x^3\right )^{2/3} \left (\frac{d x^3}{c}+1\right )^{2/3}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(x^4*(a + b*x^3)^(4/3))/(c + d*x^3),x]

[Out]

(2*(9*b^2*c^2 - 12*a*b*c*d + 2*a^2*d^2)*x^5*(1 + (b*x^3)/a)^(2/3)*(1 + (d*x^3)/c)^(2/3)*AppellF1[5/3, 2/3, 1,
8/3, -((b*x^3)/a), -((d*x^3)/c)] + 5*c*x^2*((a + b*x^3)*(-6*b*c + 7*a*d + 3*b*d*x^3)*(1 + (d*x^3)/c)^(2/3) + a
*(6*b*c - 7*a*d)*(1 + (b*x^3)/a)^(2/3)*Hypergeometric2F1[2/3, 2/3, 5/3, ((-(b*c) + a*d)*x^3)/(a*(c + d*x^3))])
)/(90*c*d^2*(a + b*x^3)^(2/3)*(1 + (d*x^3)/c)^(2/3))

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Maple [F]  time = 0.061, size = 0, normalized size = 0. \begin{align*} \int{\frac{{x}^{4}}{d{x}^{3}+c} \left ( b{x}^{3}+a \right ) ^{{\frac{4}{3}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(b*x^3+a)^(4/3)/(d*x^3+c),x)

[Out]

int(x^4*(b*x^3+a)^(4/3)/(d*x^3+c),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{3} + a\right )}^{\frac{4}{3}} x^{4}}{d x^{3} + c}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(b*x^3+a)^(4/3)/(d*x^3+c),x, algorithm="maxima")

[Out]

integrate((b*x^3 + a)^(4/3)*x^4/(d*x^3 + c), x)

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Fricas [A]  time = 11.9539, size = 1281, normalized size = 3.84 \begin{align*} \frac{2 \, \sqrt{3}{\left (9 \, b^{3} c^{2} - 12 \, a b^{2} c d + 2 \, a^{2} b d^{2}\right )} \sqrt{-\left (-b^{2}\right )^{\frac{1}{3}}} \arctan \left (-\frac{{\left (\sqrt{3} \left (-b^{2}\right )^{\frac{1}{3}} b x - 2 \, \sqrt{3}{\left (b x^{3} + a\right )}^{\frac{1}{3}} \left (-b^{2}\right )^{\frac{2}{3}}\right )} \sqrt{-\left (-b^{2}\right )^{\frac{1}{3}}}}{3 \, b^{2} x}\right ) - 18 \, \sqrt{3}{\left (b^{3} c - a b^{2} d\right )}{\left (-b c^{3} + a c^{2} d\right )}^{\frac{1}{3}} \arctan \left (-\frac{\sqrt{3}{\left (b c^{2} - a c d\right )} x + 2 \, \sqrt{3}{\left (-b c^{3} + a c^{2} d\right )}^{\frac{2}{3}}{\left (b x^{3} + a\right )}^{\frac{1}{3}}}{3 \,{\left (b c^{2} - a c d\right )} x}\right ) - 2 \,{\left (9 \, b^{2} c^{2} - 12 \, a b c d + 2 \, a^{2} d^{2}\right )} \left (-b^{2}\right )^{\frac{2}{3}} \log \left (-\frac{\left (-b^{2}\right )^{\frac{2}{3}} x -{\left (b x^{3} + a\right )}^{\frac{1}{3}} b}{x}\right ) +{\left (9 \, b^{2} c^{2} - 12 \, a b c d + 2 \, a^{2} d^{2}\right )} \left (-b^{2}\right )^{\frac{2}{3}} \log \left (-\frac{\left (-b^{2}\right )^{\frac{1}{3}} b x^{2} -{\left (b x^{3} + a\right )}^{\frac{1}{3}} \left (-b^{2}\right )^{\frac{2}{3}} x -{\left (b x^{3} + a\right )}^{\frac{2}{3}} b}{x^{2}}\right ) - 18 \,{\left (b^{3} c - a b^{2} d\right )}{\left (-b c^{3} + a c^{2} d\right )}^{\frac{1}{3}} \log \left (\frac{{\left (b x^{3} + a\right )}^{\frac{1}{3}} c +{\left (-b c^{3} + a c^{2} d\right )}^{\frac{1}{3}} x}{x}\right ) + 9 \,{\left (b^{3} c - a b^{2} d\right )}{\left (-b c^{3} + a c^{2} d\right )}^{\frac{1}{3}} \log \left (\frac{{\left (b x^{3} + a\right )}^{\frac{2}{3}} c^{2} -{\left (-b c^{3} + a c^{2} d\right )}^{\frac{1}{3}}{\left (b x^{3} + a\right )}^{\frac{1}{3}} c x +{\left (-b c^{3} + a c^{2} d\right )}^{\frac{2}{3}} x^{2}}{x^{2}}\right ) + 3 \,{\left (3 \, b^{3} d^{2} x^{5} -{\left (6 \, b^{3} c d - 7 \, a b^{2} d^{2}\right )} x^{2}\right )}{\left (b x^{3} + a\right )}^{\frac{1}{3}}}{54 \, b^{2} d^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(b*x^3+a)^(4/3)/(d*x^3+c),x, algorithm="fricas")

[Out]

1/54*(2*sqrt(3)*(9*b^3*c^2 - 12*a*b^2*c*d + 2*a^2*b*d^2)*sqrt(-(-b^2)^(1/3))*arctan(-1/3*(sqrt(3)*(-b^2)^(1/3)
*b*x - 2*sqrt(3)*(b*x^3 + a)^(1/3)*(-b^2)^(2/3))*sqrt(-(-b^2)^(1/3))/(b^2*x)) - 18*sqrt(3)*(b^3*c - a*b^2*d)*(
-b*c^3 + a*c^2*d)^(1/3)*arctan(-1/3*(sqrt(3)*(b*c^2 - a*c*d)*x + 2*sqrt(3)*(-b*c^3 + a*c^2*d)^(2/3)*(b*x^3 + a
)^(1/3))/((b*c^2 - a*c*d)*x)) - 2*(9*b^2*c^2 - 12*a*b*c*d + 2*a^2*d^2)*(-b^2)^(2/3)*log(-((-b^2)^(2/3)*x - (b*
x^3 + a)^(1/3)*b)/x) + (9*b^2*c^2 - 12*a*b*c*d + 2*a^2*d^2)*(-b^2)^(2/3)*log(-((-b^2)^(1/3)*b*x^2 - (b*x^3 + a
)^(1/3)*(-b^2)^(2/3)*x - (b*x^3 + a)^(2/3)*b)/x^2) - 18*(b^3*c - a*b^2*d)*(-b*c^3 + a*c^2*d)^(1/3)*log(((b*x^3
+ a)^(1/3)*c + (-b*c^3 + a*c^2*d)^(1/3)*x)/x) + 9*(b^3*c - a*b^2*d)*(-b*c^3 + a*c^2*d)^(1/3)*log(((b*x^3 + a)
^(2/3)*c^2 - (-b*c^3 + a*c^2*d)^(1/3)*(b*x^3 + a)^(1/3)*c*x + (-b*c^3 + a*c^2*d)^(2/3)*x^2)/x^2) + 3*(3*b^3*d^
2*x^5 - (6*b^3*c*d - 7*a*b^2*d^2)*x^2)*(b*x^3 + a)^(1/3))/(b^2*d^3)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{4} \left (a + b x^{3}\right )^{\frac{4}{3}}}{c + d x^{3}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4*(b*x**3+a)**(4/3)/(d*x**3+c),x)

[Out]

Integral(x**4*(a + b*x**3)**(4/3)/(c + d*x**3), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{3} + a\right )}^{\frac{4}{3}} x^{4}}{d x^{3} + c}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(b*x^3+a)^(4/3)/(d*x^3+c),x, algorithm="giac")

[Out]

integrate((b*x^3 + a)^(4/3)*x^4/(d*x^3 + c), x)